%[Minc]=subMinc(1); function [Minc]=subMinc(u) Minc=zeros(5,3); Minc(1,2)=-1; Minc(2,3)=-1; Minc(3,1)=-1; Minc(3,2)=1; Minc(4,2)=1; Minc(4,3)=-1; Minc(5,1)=-1; Minc(5,3)=1;